How do you solve #j/4 - 8 < 4#?

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Answer 1 · 2018-03-22T03:20:39

#j<48#

You must isolate #j# algebraically.

#j/4-8<4#

Your first step in solving this inequality is to add #8# to both sides.

#j/4<12#

Now multiply both sides by #4# to get rid of the denominator.

#color(blue)(j<48)#

So for any number, #j#, that is less than #48#, the inequality is true.
You can check this by plugging in values.

#j=52#, then #52/4-8<4 #

#=> 13-8<4#

#=> 5<4#

This is not true, strengthening the statement. Feel free to plug in other values.