How do you simplify #15a^3b^2 - 10 a^2b^2 + 14a^3b^2 - 5a^2b^2#?

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Answer 1 · 2018-03-22T09:45:43

#a^2b^2(29a-15)=(ab)^2(29a-15)#

We need the greatest common factors in each term.

First we simplify to get: #29a^3b^2-15a^2b^2#

There are no integers which divide into #29# and #15#.

#a^2# goes into #a^3# and #a^2#

All terms have #b^2#

So we factor out #a^2b^2#

#a^2b^2(29a-15)#

If you want, we can factor #a^2b^2=(ab)^2#