How do you simplify $15a^3b^2 - 10 a^2b^2 + 14a^3b^2 - 5a^2b^2$ ?

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Answer 1 · 2018-03-22T09:45:43

$a^2b^2(29a-15)=(ab)^2(29a-15)$

We need the greatest common factors in each term.

First we simplify to get: $29a^3b^2-15a^2b^2$

There are no integers which divide into $29$ and $15$ .

$a^2$ goes into $a^3$ and $a^2$

All terms have $b^2$

So we factor out $a^2b^2$

$a^2b^2(29a-15)$

If you want, we can factor $a^2b^2=(ab)^2$

How do you simplify 15a^3b^2 - 10 a^2b^2 + 14a^3b^2 - 5a^2b^215a^3b^2 - 10 a^2b^2 + 14a^3b^2 - 5a^2b^2?