What is the general form of the equation 5x^2-20x =15?

1 Answer
Mar 22, 2018

x^2-4x-3

Explanation:

5x^2-20x=15

=> 5(x^2-4x)=5(3)

=> cancel5(x^2-4x)=cancel5(3)

=> x^2-4x=3

=> x^2-4x-3=0

It is now in the general form which is ax^2+bx+c=0