How do you solve #4r + 10= - 10+ 2r - 8r#?

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Answer 1 · 2018-03-22T18:15:51

#r = -2#

#4r + 10 = -10 + 2r - 8r#

#2r - 8r = -6r#

which means that

#4r + 10 = -10 -6r#.

adding #10# to both sides,

#4r + 20 = -6r#

subtracting #4r# from both sides,

#20 = -10r#

dividing by #10#,

#2 = -r#

or

#-r = 2#

multiplying by #-1# (same as reversing the signs),

#r = -2#