Question

How do i solve this? (trig/geometry)

Answer 1

Explanation on how to do below

Explanation:

`sin(56°)= (DE)/6`

1. `DE= Sin(56°)*6= ?` Use your calculator

`cos(56°)= (EF)/6`

2.`EF= cos(56°)*6= ?` Use your calculator

`Tand= (EF)/(DE)`

3.`∠d= Tan^-1((EF)/(DE))`

Use the values of EF and DE from above

Answer 2

`DE=5.0,EF=3.4,angleD=34^@`

Explanation:

`"since the triangle is right use "color(blue)"trig. ratios"`

`•color(white)(x)sinx="opposite"/"hypotenuse",cosx="adjacent"/"hypotenuse"`

`rArrsin56^@=(DE)/6`

`rArrDE=6xxsin56^@~~5.0" to nearest tenth"`

`rArrcos56^@=(EF)/6`

`rArrEF=6xxcos56^@~~3.4" to nearest tenth"`

`• " Sum of angles in a triangle "=180^@`

`rArrangleD=180^@-(90+56)^@=34^@`