How do you solve #7x ^ { 2} - 9= 0#?

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Answer 1 · 2018-03-23T00:27:21

Read below.

We have:

#7x^2-9=0# Add #9# on both sides.

#7x^2=9# Divide both sides by 7.

#x^2=9/7# Apply square root on both sides.

#x=+-sqrt(9/7)# That is our answer!

Alternatively, we can rewrite this as #x=+-sqrt(9)/sqrt(7)#, which is equal to

#x=+-3/sqrt7#

If your teacher is picky, then you could even do this:

#3/sqrt7*sqrt7/sqrt7=>+-(3sqrt7)/7#