How do you differentiate $g(x) = (e^(2x)-e^x) ( x-x^2)$ using the product rule?

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Answer 1 · 2018-03-23T12:35:44

$g(x)=(e^(2x)−e^x)(x−x^2)$

$g'(x)=(e^(2x)−e^x)(x−x^2)' + (e^(2x)−e^x)'(x−x^2)$

derivative of $e^x$ is $e^x$ , therefore,

$=>(e^(2x)−e^x)(1−2x) + (2e^(2x)−e^x)(x−x^2)$

How do you differentiate g(x) = (e^(2x)-e^x) ( x-x^2)g(x) = (e^(2x)-e^x) ( x-x^2) using the product rule?