What are four solutions of 4x-3y=24x3y=2, using x=-1, 1, 0, 2x=1,1,0,2?

1 Answer

y=-2,2/3, -2/3, 2y=2,23,23,2

Explanation:

x=-1
4(-1)-3y=24(1)3y=2
-4-3y=243y=2
3y=-63y=6
y=-2y=2

x=1
4(1)-3y=24(1)3y=2
4-3y=243y=2
3y=23y=2
y=2/3y=23

x=0
4(0)-3y=24(0)3y=2
-3y=23y=2
y=-2/3y=23

x=2
4(2)-3y=24(2)3y=2
8-3y=283y=2
3y=63y=6
y=2y=2