How do you find the limit #(5+x^-1)/(1+2x^-1)# as #x->oo#?

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Answer 1 · 2018-03-23T18:24:42

#5#

#lim_(x->infty)(5+1/x)/(1+2/x)=(5+0)/(1+0) = 5/1 = 5#

Answer 2 · 2018-03-23T20:23:52

#5#

#lim_(xtooo)(5+x^-1)/(1+2x^-1)#

#"=lim_(xtooo)(5+1/x)/(1+2/x)#

#=(5+0)/(1+0)=5#