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Integration of cosx.sin square x ?

1 Answer

Mar 23, 2018

$= - sin (x) \cdot sin (x^{2}) + 2 x cos (x^{2}) \cdot cos (x)$ $= -sin(x)* sin(x^2) + 2xcos(x^2)*Cos(x)$

Explanation:

$cos (x) \cdot sin (x^{2})$ $Cos(x) * sin(x^2)$

Using Product rule, $(fg)^' = f'g + g'f$ :

$= -sin(x)* sin(x^2) + cos(x^2)*2x *Cos(x)$

Note: I used Chain rule to find the derivative of $Sin(x^2)$ :

$= -sin(x)* sin(x^2) + 2xcos(x^2)*Cos(x)$

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