Find the range of velocities of the blocks shown in the figure below during the motion? How do we solve this problem without seeing from the center of mass frame?

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1 Answer
Mar 24, 2018

Just take the reduced mass of the system,which will give you a single block with a spring attached to it.

Here the reduced mass is #(2*3)/(2+3)=6/5 Kg#

So,angular frequency of the motion is, #omega=sqrt(K/mu)=sqrt(500/6)=9.13 rads^-1# (given, #K=100 Nm^-1#)

Given,velocity in mean position is #3 ms^-1# and it is the maximum velocity of its motion.

So,range of velocity i.e amplitude of motion will be #A=v/omega#

so,#A=3/9.13=0.33 m#