$∠ D E F$ $angleDEF$ and $∠ F E G$ $angleFEG$ are supplementary. $m ∠ D E F = (9 x + 1)$ $mangleDEF =(9x+ 1)$ and $m ∠ F E G = (8 x + 9)$ $mangleFEG=(8x+9)$ , how do you find the measures of both angles?

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Answer 1 · 2018-03-24T09:21:14

$< D E F = 91^{0}$ $< DEF=91^0$
$< F E G = 89^{0}$ $< FEG=89^0$

Supplementary angles add up to $180^{0}$ $180^0$

$:.8x+9+9x+1=180$

now solve for $x$

$17x+10=180$

$17x=170$

$:. x=10^0$

$< DEF=9x+1=9xx10+1=91^0$

$<FEG=8x+9=8xx10+9=89^0$

angleDEF∠DEFangleDEF and angleFEG∠FEGangleFEG are supplementary. mangleDEF =(9x+ 1)m∠DEF=(9x+1)mangleDEF =(9x+ 1) and mangleFEG=(8x+9)m∠FEG=(8x+9)mangleFEG=(8x+9), how do you find the measures of both angles?