How do you solve #(9!)/(6!3!)# ?

1 Answer

Lettuce not without thinking solve its factorial and divide... expand it... I'm not writing one as it doesn't matter
#(color(red)cancel9^3xxcolor(skyblue)cancel8^4xx7xxcancel6xxcancel5xxcancel4xxcancel3xxcancel2)/(cancel6xxcancel5xxcancel4xxcancel3xxcancel2xxcolor(red)cancel3xxcolor(skyblue)cancel2)#
We are left with
#3xx4xx7#
#84#