#(x+1)(x+2)#?

It's multiplying Binomials but I just dont understand how to do it?

2 Answers
Mar 24, 2018

#x^2+3x+2#

Explanation:

Multiply each of the terms in the first set of parentheses by each of the terms in the second set of the parentheses, then add the products together

#(x*x)+(x*2)+(1*x)+(1*2)#

#x^2+2x+x+2 rarr# Combine the like terms

#x^2+3x+2#

Mar 24, 2018

#(x+1)(x+2)=x^2+3x+2#

Explanation:

When you have two numbers to multiply, you have to distribute. In order to do that, you have to take each of your number and to be sure that they are multiply once to the other number ( and to be careful with the sign ).
We've got : [1]#(color(blue)(x) +color(yellow)(1)) (x+2)=color(blue)(x*(x+2))+color(yellow)((x+2)) #
Now We've got an easier model.
[2]#(x+1)(x+2)=color(red)(x*x)+color(green)(x*2+x)+2#
[3]#(x+1)(x+2)=color(red)(x^2)+color(green)(3x)+2#
\0/ here's the answer !
if you are still in difficulty after the explanation, just do some more, here's some examples, try to find those answers:

#(x+1)(x-1)=x^2-1#,#(x-1)(x+2)=x^2+x-2#,#(x-3)(x+3)=x^2-9#