How do you solve #8y + 26= - 2( y + 2)#?

1 Answer

#y = -3#.

Explanation:

We have,

#color(white)(xxx)8y + 26 = -2(y + 2)#

#rArr 8y + 26 = -2y - 4#

[Just use the distributive property to simplify the R.H.S]

#rArr 8y + 2y + 26 = cancel(-2y) - 4 cancel(+2y)# [Add #2y# to both sides.]

#rArr 10y + 26 = -4#

#rArr 10y cancel(+ 26) cancel(- 26) = -4 - 26# [Subtract #26# from both sides]

#rArr 10y = -30#

#rArr y = -30/10# [Divide both sides by #10#]

#rArr y = -3#

Hence Explained.