How do you solve #3v + 6\leq - 12#?

Question

361 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-25T04:54:24

The solutions is #v<=-6#.

Treat the inequality like a regular equation. Subtract #6# from both sides, then divide by #3#. The process looks like this:

#3v+6<=-12#

#3v+6color(blue)-color(blue)6<=-12color(blue)-color(blue)6#

#3vcolor(red)cancelcolor(black)(color(black)+color(black)6color(blue)-color(blue)6)<=-12color(blue)-color(blue)6#

#3v<=-12color(blue)-color(blue)6#

#3v<=-18#

#color(blue)(color(black)(3v)/3)<=color(blue)(color(black)(-18)/3)#

#color(blue)(color(black)(color(red)cancelcolor(black)3v)/color(red)cancelcolor(black)3)<=color(blue)(color(black)(-18)/3)#

#v<=color(blue)(color(black)(-18)/3)#

#v<=-6#

That's the solution. Hope this helped!