What is the value of #3+y-:4#, when #y=16#?

3 Answers
Mar 26, 2018

The answer is #7.#

Explanation:

First, you plug the # y = 16# into the problem, so it looks like this:
# 3 + 16 /4#

Then follow PEMDAS.
#3 + (16/4)#
#3 + (4)#
#7#

Mar 26, 2018

See below.

Explanation:

When solving this expression, first we need to remember to follow the Order of Operations .

This operation is commonly referred to as #PEMDAS#. This is an acronym used by many in a way to remember these important steps:

#P# - Parenthesis

#E# - Exponents

#MD# - Multiply/Divide (left to right)

#AS# - Add/Subtract (left to right)

Now that we know this, we can being to simplify this expression. Luckily for us, it has given us the value of #y#, so all we have to do is to plug said value into the expression:

#3+ydivide4 => 3+(16)divide4#

Now we simply solve using the above steps in order form top to bottom:

#3+(16)divide4#

#=3+4#

#=7#

Mar 26, 2018

#7#

Explanation:

Be careful about the order of operations.

There are two terms. Calculate an answer for each first, which means doing the division of the second term first.

#color(blue)(3)" "+" "color(red)(y div4)#

#=color(blue)(3)" "+" "color(red)(16 div4)#

#=color(blue)(3)" "+" "color(red)(4)#

#=7#