How do you solve #-x + 3= 5#?

Question

1062 views around the world

You can reuse this answer
Creative Commons License

Answer 1 · 2018-03-28T02:11:18

x = -2

#-x + 3 = 5#

Subtract 3 on both sides of the equation.

#-x = 2#

Divide by -1 on both sides.

#x = -2#

Answer 2 · 2018-03-28T02:11:59

The solution is #x=-2#.

First, subtract #3# from both sides, then multiply both sides by #-1#:

#-x+3=5#

#-x+3color(blue)-color(blue)3=5color(blue)-color(blue)3#

#-xcolor(red)cancelcolor(black)(color(black)+3color(blue)-color(blue)3)=5color(blue)-color(blue)3#

#-x=5color(blue)-color(blue)3#

#-x=2#

#-xcolor(blue)(*-1)=2color(blue)(\*-1)#

#color(red)cancelcolor(black)-xcolor(blue)(*color(red)cancelcolor(blue)-1)=2color(blue)(\*-1)#

#xcolor(blue)(*1)=2color(blue)(\*-1)#

#x=2color(blue)(\*-1)#

#x=-2#

That's the answer. Hope this helped!