Question

How many moles of solute particles are present in 1 mL (exact) of aqueous 0.033 M pyridine `C_5H_5N`?

Answer 1

`3.3 × 10^-5\ "moles"`

Explanation:

`"Molarity" = "Moles of solute"/"Volume of solution (in litres)"`

`"n = Molarity × Volume"`

`"n = 0.033 M × 1 mL"`

`"n" = 0.033 "mol"/cancel"L" × 10^-3 cancel"L" color(white)(..)[∵ "M = mol/L & 1 mL" = 10^-3\ "L"]`

`"n" = 3.3 × 10^-5\ "mol"`