What is the magnitude of the vector #<4,-2>#?

1 Answer
Mar 29, 2018

#2\sqrt{5}#

Explanation:

The magnitude of a vector can be calculated by taking the square root of the sum of the squares of the vector components.

Think about it, if you go 4 units to the right and 2 units down and you are trying to find the magnitude then you are basically faced with a right triangle. The magnitude would be the hypotenuse of the right triangle that has legs of lengths 4 and 2.

#\sqrt{4^2 + 2^2} = 2\sqrt{5}#

Therefore, the magnitude of the vector #[4, -2]# is #2\sqrt{5}#.