In triangle ABC, angle B = 23 , side c = 43m, and side a = 19m. How do you find side b?

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Answer 1 · 2018-03-29T09:13:10

$b~~26.57m$ .

By the cosine formula,

$b^2=c^2+a^2-2ac*cosB$ ,

$=43^2+19^2-2*43*19*cos23^@$ ,

$=1849+361-1634*0.921$ ,

$=2210-1504.105$ ,

$=705.895$ .

$rArr b=sqrt705.895~~26.57m$ .