Question

What is the value of θ in tan(7θ+10)=1/tan(5θ-4)?

Answer 1

`tan(7θ+10)=1/tan(5θ-4)`

`=>tan(7θ+10)=cot(5θ-4)`

`=>tan(7θ+10)=tan(pi/2-(5θ-4))`

`=>7θ+10=npi+pi/2-5θ+4" where "ninZZ`

`=>12θ=npi+pi/2-6" where "ninZZ`

`=>θ=((2n+1)pi)/24-1/2" where "ninZZ`