how do you change #y=-2x^2+8x-1# to vertex form?

1 Answer
Douglas K.
Mar 29, 2018

When given a quadratic equation #y = ax^2+bx+c#, the x coordinate of the vertex is, #h = -b/(2a)# and the y coordinate of the vertex is #k = a(h)^2+b(h)+c# then use the form #y = a(x-h)^2+k#

Explanation:

Applying the information in the answer to the given equation:

#h = -8/(2(-2))#

#h = 2#

#k = -2(2)^2+8(2)-1#

#k = 7#

Substitute #a = -2, h = 2, and k = 7# into the form:

#y = -2(x-2)^2+7#

Related questions
Impact of this question
5813 views around the world
You can reuse this answer
Creative Commons License