How do you solve #(1/1000)^(-1/3)#? Algebra Expressions, Equations, and Functions Problem-Solving Models 2 Answers Harshit Tiwari Mar 30, 2018 #10# Explanation: #(1/1000)^-(1/3)# #=1/1000^-(1/3)# #=1000^(1/3)# #=root(3) 1000# #=10# Answer link mizoo Mar 30, 2018 #(1/1000) ^(-1/3) = 10# Explanation: # (1/1000) ^(-1/3)# # = ((1000/1)^-1)^(-1/3)# # = 1000^(-1 xx-1/3)# # = 1000^(1/3)# #= (10^3)^(1/3) # #= 10^(3xx1/3) # #= 10# Answer link Related questions What are the steps to solving a word problem? Where do I start when I'm trying to solve a word problem? How do you check a solution to a problem? What are the different strategies used to solve a word problem? What is the best method of determining the cost of downloading 26 movies, if it cost $2.25 to... How do you solve word problems involving percents? What are commonly used math terms that translates to addition, subtraction, multiplication, and division? How much pure antifreeze should be added to 3 gallons of a 30 percent antifreeze solution to get... How would you use equations to calculate the age of Al given that Al's father is 45 and he is 15... How do you solve #x=(y-1)/(y+1)# for y? See all questions in Problem-Solving Models Impact of this question 11460 views around the world You can reuse this answer Creative Commons License