How do you solve the system of equations #y- 3x = 3# and #x - 2y = 4#?

1 Answer
Mar 30, 2018

#x=-2# and #y=-3#

Explanation:

We can take double the first plus the second to isolate #x#:

#2y-6x=6 #
#-2y + x = 4 #
#-5x = 10 implies x = -2 #

Plugging that in to the first equation:
#y - 3(-2) =3 implies y + 6 = 3 implies y = -3 #