How do you evaluate #x^3 + 5# when x = 4?
1 Answer
Mar 31, 2018
Explanation:
#"substitute x = 4 into the expression"#
#rArr(color(red)(4))^3+5#
#=(color(red)(4)xxcolor(red)(4)xxcolor(red)(4))+5#
#=(16xxcolor(red)(4))+5=64+5=69#
