Question

Write an equation for the line ?

A straight line from the origin passes through the point P(x,y) in the first quadrant and is inclined at `θ = (pi)/(3)` from the positive x-axis. Write an equation for the line.

Answer 1

`y=1/sqrt3x`

Explanation:

Given:

`theta=pi/3`

Slope is

`m=tan theta`

`tan theta = tan (pi/3)`

`tan(pi/3)=1/sqrt3`

`m=1/sqrt3`

Equation of the straight line passing through the origin and having slope m is given by

`y=mx`

`y=1/sqrt3x`