Question

How do you solve `m^ { 2} + 15m - 16= 0`?

Answer 1

`m^ { 2} + 15m - 16= 0`

`=>m^2 + 16m - m - 16= 0`

`=>m(m + 16)- 1(m + 16)= 0`

`=>(m-1)(m + 16)= 0`

Therefore either, `(m-1)= 0` or `(m + 16)= 0`

so, `color(red)(m=1` or `color(red)(m=-16`