What is #(3 sqrt5)/sqrt7#?

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Answer 1 · 2018-04-01T06:21:11

The expression is equal to # (3sqrt35)/7 #.

Rationalize the denominator by multiplying the top and bottom of the fraction by #sqrt7#:

# color(white)=(3sqrt5)/sqrt7 #

# =(3sqrt5)/sqrt7color(red)(*sqrt7/sqrt7) #

# =(3sqrt5*sqrt7)/(sqrt7*sqrt7) #

# =(3sqrt5*sqrt7)/(sqrt7)^2 #

# =(3sqrt5*sqrt7)/7 #

# =(3sqrt35)/7 #

# ~~2.53546... #