What is the oxidation no. Of Mn in MnCl2?

2 Answers

In #MnCl_2#, the oxidation state of #Mn# would be #+2#.

Explanation:

I would list every rule of assigning oxidation numbers here by myself, but I don't have much time (;-P).

See them here :- Rules of Assigning Oxidation Numbers

Now, on with our answer.

First of All, In #MnCl_2#, #Cl^-# has a charge of #-1#.

So, We will assign #-1# state to #Cl#.

And, In every molecule, the oxidation numbers of all atoms add up to #0#.

So, If we assume the oxidation number of #Mn# be #x#.

So, According to the rules and the question,

#x + 2 * (-1) = 0 rArr x -2 = 0 rArr x = 2#

So, #Mn# has a oxidation number #+2# here.

[NEVER, NEVER forget to assign the SIGNS. OXIDATION NUMBER denotes state, it isn't just a number.]

Hope this helps.

Apr 1, 2018

#+2#

Explanation:

Manganese chloride has a chemical formula of #MnCl_2#. It is a neutral compound, meaning that the sum of all oxidation states of the compounds is #0#.

In this case, it is an ionic compound, as there is a metal (manganese) and a non-metal (chlorine) bonded together. And so, chlorine is the anion, and will have a charge of #-1#. There are two chlorine atoms, and the total oxidation number will be #-1*2=-2#.

Let #x# be the oxidation number of manganese. We got:

#x+(-2)=0#

#x-2=0#

#x=2#

Therefore, manganese's #(Mn)# oxidation state is #2# or #+2#, as we say in chemistry.