How do you multiply #(4x - 8) ( 2x - 9)#?

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Answer 1 · 2018-04-01T23:08:31

#8x^2-52x+72#

#(4x-8)(2x-9)#

We want to multiply it out like this:
#4x * 2x = 16x^2#

#-8 * 2x = -16x#

#4x * -9 = -36x#

#-8 * -9 = 72#

When you add them all together it becomes:
#8x^2-16x-36x+72#

We can still simplify the #-16# and #-36#, so the final answer becomes:
#8x^2-52x+72#

Hope this helps!

Answer 2 · 2018-04-01T23:10:42

#8x^2-52x+72#

#(4x-8)(2x-9)#

#4x*2x+4x*(-9)-8*2x-8*(-9)#

#8x^2-36x-16x+72#

#8x^2-52x+72#