How to find these type of question easily, without using L-hopitals rule?
2 Answers
Apr 2, 2018
Explanation:
but for small
Apr 2, 2018
Please see below.
Explanation:
As Cesareo points out:
# = sin(pi -pi sin^2)/x^2# #" "# (now use the difference formula)
# = sin(pi sin^2 x)/x^2#
# = sin(pi sin^2 x)/1 1/x^2#
# = sin(pi sin^2 x)/(pisin^2x) (pisin^2x)/x^2#
# = sin(theta)/(theta) pi (sinx/x)^2#
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