Write sec theta - tan theta sin theta in terms of sin theta and cos theta; then simplify if possible. (Leave your answer in terms of sin theta and/or cos theta)? See details for the problem

#sin theta - tan theta sin theta#

1 Answer
Apr 3, 2018

Hope this helps

Explanation:

#sec theta - tan theta sin theta =(1/(cos theta))-(sin^2 theta)/(cos theta)#
But #1-sin^2 theta = cos^2 theta#. Hence
#= cos^\cancel(2) theta/(\cancel(cos theta)#
#sec theta - tan theta sin theta=cos theta#