How to integrate ∫ (x^2−9)^(3/2) dx?
#int (x^2-9)^(3/2)dx#
I have used substitution x=3 sec u and can go up to
81 ∫ （sec u)^5 -2 （sec u)^3 +sec u) du.
I then try to use t=tan(u/2) to solve ∫ （sec u)^5 du but end up in a mess.
Please help.
I have used substitution x=3 sec u and can go up to
81 ∫ （sec u)^5 -2 （sec u)^3 +sec u) du.
I then try to use t=tan(u/2) to solve ∫ （sec u)^5 du but end up in a mess.
Please help.
2 Answers
Apr 2, 2018
Solved!
Explanation:
use reduction formula or integration by parts to integrate (sec u)^5
Apr 3, 2018
I have solved this way.
