Question

How do you solve `x^2 + 8x - 41 = -8` by completing the square?

Answer 1

`x^2+8x-41=-8`

`x^2+8x-41+8=0`

`x^2+8x-33=0`

`(x^2+8x+16-16)-33=0` `larr` you get 16 by dividing 8 by 2 and `color(white)"XXXXXXXXXXXXXXXXXX"`squaring the value (8`-:`2= 4), `4^2` = 16

`(x+4)^2-49=0`