What is the square root of #8/18#?

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Answer 1 · 2018-04-04T03:01:52

#2/3#

We want #sqrt(8/18)#

Recalling that #sqrt(a/b)=sqrta/sqrtb,# we get

#sqrt8/sqrt18#

We need to simplify these roots.

#sqrt8=sqrt(4*2)=sqrt4sqrt2=2sqrt2#

#sqrt(18)=sqrt(9*2)=sqrt9sqrt2=3sqrt2#

So, we then have

#(2cancelsqrt2)/(3cancelsqrt2)=2/3#