Factors of #x^2-x-20?#

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Answer 1 · 2018-04-05T05:10:14

See below...

Let's use middle term factor process.

#x^2-x-20#
#=x^2+4x-5x-20#
#=x(x+4)-5(x+4)#
#=(x+4)(x-5)#

There are two factors of the given expression.

Hope it helps...
Thank you...

Answer 2 · 2018-04-05T05:12:30

The factors are, #color(red)((x-5)# and #color(red)((x+4)#

#x^2−x−20#

Split the middle term in such a way, that when the coefficients are added they give #-1# and when multiplied give #-20#.

#=x^2+4x-5x−20#

#=x(x+4)-5(x+4)#

#=(x-5)(x+4)#

Therefore the factors are, #color(red)((x-5)# and #color(red)((x+4)#