How do you simplify $h(x)= log (x^2+6x+9)(sqrt(x^2-1))$ ?

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Answer 1 · 2018-04-05T11:17:47

$2log(x+3)+1/2log(x^2-1)$

Factor: $x^2+6x+9$

$(x+3)^2$

$sqrt(x^2-1)=(x^2-1)^(1/2)$

$:.$

$log(x+3)^2(x^2-1)^(1/2)$

$->log(x+3)^2+log(x^2-1)^(1/2)$

$->2log(x+3)+1/2log(x^2-1)$

This is as far as I can go.

How do you simplify h(x)= log (x^2+6x+9)(sqrt(x^2-1))h(x)= log (x^2+6x+9)(sqrt(x^2-1))?