How do you solve $log (4p-2)=log(-5p+5)$ ?

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Answer 1 · 2018-04-05T14:37:15

$color(blue)(7/9)$

If:

$log(4p-2)=log(-5p+5)=>4p-2=-5p+5$

$4p-2=-5p+5$

$9p=7$

$p=7/9$

Check:

$log(4(7/9)-2)=log(-5(7/9)+5)$

$log(10/9)=log(10/9)$

How do you solve log (4p-2)=log(-5p+5)log (4p-2)=log(-5p+5)?