Prove the identity Tan^2x-sin^2x is same as (tan^2x)(sin^2x)?

1 Answer
Sahar Mulla ❤
Apr 6, 2018

#Tan^2x-sin^2x #

#=> sin^2x/cos^2x-sin^2x # #color(white)(wwwwwwwww# #["as " tanx = sinx/cosx]#

#=> (sin^2x - sin^2xcos^2x)/cos^2x#

#=> (sin^2x(1 - cos^2x))/cos^2x# #color(white)(wwwwww# #["as " sin^2x + cos^2x =1]#

#=> (sin^2x(sin^2x))/cos^2x#

#=>tan^2xsin^2x#

Related questions
Impact of this question
7329 views around the world
You can reuse this answer
Creative Commons License