What is the antiderivative of 1/(2x + 1) dx?

I started with a "u" substitution for 2x + 1 but I don't think that's correct.

1 Answer
Mahek ☮
Apr 6, 2018

Yes, you we're going right.

Let #2x + 1 = u#

#du= 2 dx => dx = (du)/2#

Replacing this in the given question.

#=>int 1/(2x + 1) dx#

#=>int 1/u (du)/2#

#=>1/2 int 1/u du#

#=>1/2 log|u| +c#

Replacing again,

#=>1/2 log|2x+1| +c#

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