Question

John is going to pack 2 T-shirts for basketball practice. He has 2 White shirts, 3 blue shirts, 1 green shirt, and 3 black shirts in her drawer. If John chooses the 2 shirts at random, What is the probability that he will pack 2 blue T-shirts?

Answer 1

There is a `1/12` chance of John packing 2 blue shirts for basketball practice.

Explanation:

                      Probability is calculated by having

`"The number of events that you get what you want"/"The possible number of outcomes"`

Now since John is picking 2 shirts, there are 2 probabilities that depend on each other because once John picks a shirt, it is no longer a possible outcome.

So our first probability is `3/9` because there are 3 blue shirts and 9 shirts in total and our second probability is `2/8` because if he does get that first blue shirt, there will only be 2 blue shirts and 8 shirts in total.

When you want to find the probability of 2 events, you must multiply the probabilities of each event with each other. Therefore our final equation is `3/9` x `2/8` which equals `6/72` which simplifies down to `1/12`.

Answer 2

`1/12to(C)`

Explanation:

`"the total number of shirts "=2+3+1+3=9`

`"Probability is calculated using the formula"`

`"probability "="possible number of favourable outcomes"/"total count"`

`"here the total count "=9`

`"favourable outcome is a blue shirt"`

`P("blue shirt")=3/9=1/3`

`"there is no replacement s there are now 2 blue shirts and"`
`"the count is 8"`

`P("second blue shirt")=2/8=1/4`

`P("2 blue shirts")=1/3xx1/4=1/12to(C)`