How do you solve #-5<a+2#?

1 Answer
Apr 7, 2018

See a solution process below:

Explanation:

Subtract #color(red)(2)# from each side of the inequality to solve for #a# while keeping the inequality balanced:

#-5 - color(red)(2) < a + 2 - color(red)(2)#

#-7 < a + 0#

#-7 < a#

We can write the solution in terms of #a# by reversing or "flipping" then entire inequality:

#a > -7#