What is the value of? 1/3÷4

3 Answers
Apr 1, 2018

#1/12# is the value.

Explanation:

What you do is the KCF method. Keep, Change, Flip. You would keep the #1/3#. Then you change the divide sign to a multiply sign. Then you flip the #4# to #1/4#. You do that since #1/4# is the reciprocal of #4#.

#1/3 div 4 = 1/3 xx 1/4#

Apr 2, 2018

#1/12#

Explanation:

You can work it out using the usual fraction division process, or just through what is happening...

If you take one third and cut it in half ( same as dividing by #2#), then each piece will be #1/6#. (More pieces, therefore they get smaller)

If you take #1/6# and cut it in half, the pieces get smaller again. Each piece will be #1/12#

#1/3 div 4 = 1/3 div 2 div 2 = 1/12#

A nifty short cut: To divide a fraction in half, either halve the top (if it is even) or double the bottom:

#2/3 div 2 = 1/3#

#4/11 div 2 = 2/11" "larr# pretty obvious if you think about it!!

#5/9 div 2 = 5/18#

#7/8 div 2 = 7/16#

In the same way: To divide a fraction by #3# in half, either divide the by #3# (if possible) or treble the bottom:

#6/11 div 3 = 2/11" "larr# share out #6# portions equally.

#5/8 div 3 = 5/24#

Apr 7, 2018

This is why the 'turn upside down and multiply' works.

Explanation:

#color(blue)("Answering the question using the shortcut method")#

Write as #1/3-: 4/1#

giving: #1/3xx1/4= (1xx1)/(3xx4)=1/12#
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#color(white)()#

#color(blue)("The teaching bit")#

A fraction structure is such that we have:

#("numerator")/("denominator") ->("count")/("size indicator of what you are counting")#

YOU CAN NOT #color(red)(ul("DIRECTLY"))# ADD, SUBTRACT OR DIVIDE ONLY THE COUNTS UNLESS THE SIZE INDICATORS ARE THE SAME.

You have been applying this rule for years without realising it!
Consider the numbers: 1,2,3,4,5 and so on. Did you know that it mathematically correct to write them as: #1/1,2/1,3/1,4/1,5/1# and so on. So their SIZE INDICATORS ARE THE SAME.
~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~~
#color(blue)("Explaining the principle using a different example")#

#color(brown)("I have chosen to use a different example as I wished")##color(brown)("to avoid using 1's. In avoiding 1's the behaviour is more obvious.") #

Consider the example #color(green)(3/color(red)(4)-:2/color(red)(8)")#

Turn upside down and change the sign to multiply

#color(green)(3/color(red)(4)xxcolor(red)(8)/2 larr" as per the method"#

Note that: #4xx2=8 =2xx4.# This is commutative.

Using the principle of being commutative swap the 4 and 2 round the other way giving:

#color(green)(color(white)("ddd")ubrace(3/2)color(white)("ddd")xxcolor(white)("ddd")color(red)(ubrace(8/4)) #

#color(green)("directly dividing ") color(red)("Converting the")#
#color(green)(color(white)("dd")"the counts")color(white)("ddddddd") color(red)("counts")#

Now split them up like this:

#( color(green)( 3)xxcolor(red)(8/4)) -:color(green)(2)#

#color(magenta)(color(white)("ddd") 6 color(white)("dddd")-:2)#

And compare to the original of #color(green)([3/color(red)(4)]-:2/color(red)(8)")#

#color(white)()#

#color(green)([3/color(red)(4)color(black)(xx2/2)] color(green)(-:)2/color(red)(8))color(white)("dddd")->color(white)("dddd")color(magenta)(6)/8-:color(magenta)(2)/8#
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So the #color(red)(8/4)# is the equivalent action of making the size indicators the same and adjusting the counts to suit.

#color(red)("IT IS A CONVERSION FACTOR")#
So by turning upside down' and multiplying you are applying a conversion and directly dividing the counts all at once.