Question

How do you solve `8v ^ { 2} + 8v + 2= 0` using the quadratic formula?

Answer 1

`v=-1/2`

Explanation:

The quadratic formula for `ax^2+by+c=0` is given by `x=(-b+-sqrt(b^2-4ac))/(2a)`

So, `v=(-8+-sqrt(8^2-4(8)(2)))/(2(8))`
`v=(-8)/16=-1/2`