How do you simplify #sqrt5 (sqrt8 + sqrt5)#? Algebra Radicals and Geometry Connections Multiplication and Division of Radicals 1 Answer Jade Apr 9, 2018 #2sqrt10+5# Explanation: #sqrt5(sqrt8+sqrt5)# #rArr sqrt40+(sqrt5)^2# #rArr 2sqrt10+5# That's it, Hope this helps :) Answer link Related questions How do you simplify #\frac{2}{\sqrt{3}}#? How do you multiply and divide radicals? How do you rationalize the denominator? What is Multiplication and Division of Radicals? How do you simplify #7/(""^3sqrt(5)#? How do you multiply #(sqrt(a) +sqrt(b))(sqrt(a)-sqrt(b))#? How do you rationalize the denominator for #\frac{2x}{\sqrt{5}x}#? Do you always have to rationalize the denominator? How do you simplify #sqrt(5)sqrt(15)#? How do you simplify #(7sqrt(13) + 2sqrt(6))(2sqrt(3)+3sqrt(6))#? See all questions in Multiplication and Division of Radicals Impact of this question 1173 views around the world You can reuse this answer Creative Commons License