Question

What is Y = x^2 - 6x - 15 in vertex form?

Answer 1

The general vertex form is `y=a(x−h)^2+k` where `(h,k)` is the vertex.

Explanation:

`y=x^2 - 6x - 15`

`y=x^2-6x +9 - 9 - 15`

`y=(x^2−6x+9)−24`

Vertex form:
`f(x)=(x−3)^2−24`

Vertex:
`(3,−24)`