How do I write an equation for the line passing through (-2,4) and (-3,3)?
2 Answers
Explanation:
#"the equation of a line in "color(blue)"slope-intercept form"# is.
#•color(white)(x)y=mx+b#
#"where m is the slope and b the y-intercept"#
#"to calculate m use the "color(blue)"distance formula"#
#•color(white)(x)m=(y_2-y_1)/(x_2-x_1)#
#"let "(x_1,y_1)=(-2,4)" and "(x_2,y_2)=(-3,3)#
#rArrm=(3-4)/(-3-(-2))=(-1)/(-1)=1#
#rArry=x+blarrcolor(blue)"is the partial equation"#
#"to find b substitute either of the 2 given points into"#
#"the partial equation"#
#"using "(-2,4)" then"#
#4=-2+brArrb=4+2=6#
#rArry=x+6larrcolor(red)"in slope-intercept form"#
y=1x+6
Explanation:
So here we'll use the formula y=kx+m which is a linear equation.
To get k we have to have to points and then take y1-y2/x1-x2, so let me show you with maths.
So now we know k = 1 so now we have
And now we can put in on of the two points you gave us so either (-2,4) (-3,3). I personally put in (-3,3) just because.
so we get:
Now we can solve M
And now we have the entire formula which i:
You can double check my by putting in on of your points in the equation.
Hopes this helps!