How do you solve #x - y = 11# and #x + y = 1# using substitution?

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Answer 1 · 2018-04-10T07:56:30

#therefore x = 6 " and " y = -5 #

Rearrange first equation

#x-y = 11 #

#=> x = 11 + y #

Substitute this into the second equation...

#=> ( 11 + y ) + y = 1 #

#=> 11 + 2y = 1 #

#=> 2y = -10 #

#=>color(red)( y = -5 #

We know #x = 11+y #

#=> x = 11 + (-5 ) #

#=> color(red)(x = 6 #

#color(blue)(therefore x = 6 " and " y = -5 #