How do you condense $lnx-3ln(x+1)$ ?

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Answer 1 · 2018-04-10T12:35:38

$ln x/(x+1)^3$

We have an expression:

$ln x - 3ln(x+1)$

We use two properties of logarithms:

$alogb -= logb^a$ and $log a-logb -= log(a/b)$

Applying the first property we can write the expression as:

$ln x - ln(x+1)^3$

And applying the second property we can write the expression as:

$ln (x/(x+1)^3)$

How do you condense lnx-3ln(x+1)lnx-3ln(x+1)?